[NTLUG:Discuss] bash question: executing a list of commands

[gan hawk]

Hi,

while read i; do `echo $i`; done < foo


seems to work for me. foo contained list of commands
echo a
echo b
echo c

and it printed
a
b
c

Ganesh



>From: Lance Simmons <lance at lsimmons.net>
>Reply-To: NTLUG Discussion List <discuss at ntlug.org>
>To: discuss at ntlug.org
>Subject: [NTLUG:Discuss] bash question: executing a list of commands
>Date: Sun, 22 Feb 2004 21:45:56 -0600
>
>Suppose I have a file named foo  with a series of commands I want
>execute.  E.g.,
>
>	ls -l
>	ls -lt
>	ls -ltr
>
>How do I execute the lines of foo in order?  I've tried
>
>	for i in `cat foo`; do "$i"; done
>	for i in "`cat foo`"; do "$i"; done
>
>and several others, but haven't been able to make it work.
>
>I've tried using xargs, by editing foo to contain only the lines
>
>	-l
>	-lt
>	-ltr
>
>and then doing
>
>	xargs -p ls < foo
>
>but the resulting command line is
>
>	ls -l -lt -ltr
>
>not the desired
>
>	ls -l
>	ls -lt
>	ls -ltr
>
>What am I missing?  How do I take an arbitrary list of commands and
>execute them seriatim?
>
>(As to why I don't just put the commands in a script and execute them
>directly, the answer is that I want to build the list of commands as
>output from another command.  In other words, I want the equivalent of
>the find command's -exec option.)
>
>--
>Lance Simmons
>
>_______________________________________________
>https://ntlug.org/mailman/listinfo/discuss

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