[NTLUG:Discuss] Perl help

Michael Barnes barnmichael at gmail.com
Wed Feb 6 13:10:17 CST 2008


Thanks, Eric.  This works fine run from command line in the folder
containing the desired files.
However, I need to include it into a script along with a bunch of
other things.  It will not be in the folder containing the files.

I have tried

$n = glob "/path/to/files/*";

which, of course does not work.

I guess I need to get a

foreach $n (@files) {

type of thing in there, but I can't get it to work.

Thanks for your kind assistance.

Michael

On Feb 5, 2008 4:33 PM, Eric Waguespack <ewaguespack at gmail.com> wrote:
> perl -e 'for $n ( 31000 .. 31500 ) { if ( ! -e "$n.wav" ) { print
> "$n.wav\n"; exit }}; done'
>
> ./e
>
>
> On Feb 5, 2008 4:10 PM, Michael Barnes <barnmichael at gmail.com> wrote:
> > I'm looking for a quick perl script and my brain just isn't
> > functioning right now.
> >
> > I have a folder full of audio files.  Each file is a five digit
> > number.wav, i.e. 12345.wav.
> >
> > Files are entered in this folder into particular groups of numbers, so
> > there are lots of gaps.
> >
> > I need to search a range of these files from 31000.wav to 31500.wav
> > (ignoring everything below 31000 and above 31500) and find the largest
> > available file number to use.  There may be files 31000.wav-31057.wav
> > in use,  (There would be no files 31058-31500) making 31058 the next
> > available file.
> >
> > All I need to do is get the next number (31058 in this case) into a
> > variable to be used elsewhere.
> >
> > I know this should be quite easy, but I sure can't get my head around
> > it right now.
> >
> > Thanks for any help you can come up with.
> >
> > Michael
> >



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