[NTLUG:Discuss] Perl help
Stuart Johnston
saj at thecommune.net
Wed Feb 6 13:54:51 CST 2008
You can use Eric's solution by simply prepending the path:
my $path = '/path/to/files';
for $n ( 31000 .. 31500 ) { if ( ! -e "$page/$n.wav" ) ...
Michael Barnes wrote:
> Thanks, Eric. This works fine run from command line in the folder
> containing the desired files.
> However, I need to include it into a script along with a bunch of
> other things. It will not be in the folder containing the files.
>
> I have tried
>
> $n = glob "/path/to/files/*";
>
> which, of course does not work.
>
> I guess I need to get a
>
> foreach $n (@files) {
>
> type of thing in there, but I can't get it to work.
>
> Thanks for your kind assistance.
>
> Michael
>
> On Feb 5, 2008 4:33 PM, Eric Waguespack <ewaguespack at gmail.com> wrote:
>> perl -e 'for $n ( 31000 .. 31500 ) { if ( ! -e "$n.wav" ) { print
>> "$n.wav\n"; exit }}; done'
>>
>> ./e
>>
>>
>> On Feb 5, 2008 4:10 PM, Michael Barnes <barnmichael at gmail.com> wrote:
>>> I'm looking for a quick perl script and my brain just isn't
>>> functioning right now.
>>>
>>> I have a folder full of audio files. Each file is a five digit
>>> number.wav, i.e. 12345.wav.
>>>
>>> Files are entered in this folder into particular groups of numbers, so
>>> there are lots of gaps.
>>>
>>> I need to search a range of these files from 31000.wav to 31500.wav
>>> (ignoring everything below 31000 and above 31500) and find the largest
>>> available file number to use. There may be files 31000.wav-31057.wav
>>> in use, (There would be no files 31058-31500) making 31058 the next
>>> available file.
>>>
>>> All I need to do is get the next number (31058 in this case) into a
>>> variable to be used elsewhere.
>>>
>>> I know this should be quite easy, but I sure can't get my head around
>>> it right now.
>>>
>>> Thanks for any help you can come up with.
>>>
>>> Michael
>>>
>
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